Question

how many gram of KCL must be added to 25.0 gram of water to produce a solution that is 2.25 molal.
molecular weight of KCL is equal to 74.5 can we solve​

Answer 1

Hi there,

♤ Key

☆ Molality is number of solute mols divided over mass of solvent in kg.

**********************************************

♤ Given

● Mass of solvent (water) = 25 gm = 0.025 kg

● Molality of solution = m = 2.25

● Mwt=Molar mass of solute KCl = 74.5

******************************************

◇Calculate number of solute moles by multiple the molality by mass of solvent

☆ m = n ÷ kg

So,

☆ n = m×kg= 2.25×0.025 =

0.056 mol

◇ Calculate mass of solute by multiple moles (n) by molar mass (Mwt)

☆ ms = n × Mwt = 0.056×74.5=

4.17 gm of KCl

♡ Hope the answer is helpful

♡ Plz mark it as brainliest answer