how many gram of magnesium sulphide is produced when one gram mg reacts with 1 gram sulphur? what is the weight of the residue obtained?
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Explanation:
Mg + S → MgS 24g 32g 56g 0.75g 1g 1.75g
As given in the question, mass of both Mg and S take part in the reaction in 1g. So, in this case limiting reagent is S, because 1g of S reacts completely with 0.75g of Mg. So according to the above equation 1g of S and 0.75g of Mg react to produce 1.75g of MgS.
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