Chemistry, asked by shreyagarg2170, 1 year ago

How many gram of methane are required to use 16g of O2 for combustion...?​

Answers

Answered by kylewalters6
0

Answer:

Explanation:

So 1 mole of methane requires 2 moles of oxygen for complete combustion. So 16 g of Methane requires 64 g of oxygen for the complete combustion. So 8 g of Methane requires = 8x64/16=32 g of oxygen.

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