Question

How many gram of o2 is required for combustion 480g of mg? Find the mass of mgo formed in this reaction.

Answer 1

320gm of oxygen is required for combustion of magnesium and thus 800gm of magnesium oxide is formed

Answer 2

Answer:

Mass of oxygen required for the combustion of the 480 g of magneisum is 315.84 g.

The mass of MgO formed in this reaction is 795.7194 g.

Explanation:

$2Mg+O_2\rightarrow 2MgO$

Moles of magnesium metal =$\frac{480 g}{24.31 g/mol}=19.74 moles$

According to reaction 2 moles of magnesium reacts with 1 mole of oxygen.

The 19.74 moles of magnesium will reactr with:$\frac{1}{2}\times 19.74$ moles of oxygen that is 9.87 moles.

Mass of 9.87 moles of oxygen =$9.87 mol\times 32 g/mol=315.84 g$

Mass of oxygen required for the combustion of the 480 g of magneisum is 315.84 g.

According to reaction ,2 moles of magnesium gives 2 moles of magnesium oxide

Then 19.74 moles of magnesium will give :$\frac{2}{2}\times 19.74$ moles of magnesium oxide that is 19.74 moles.

Mass of 19.74 MgO=$19.74 mole\times 40.31 mol/g =795.7194 g$

The mass of MgO formed in this reaction is 795.7194 g.