Question

How many gram of o2 is required for combustion 480g of mg? Find the mass of mgo formed in this reaction

Please answer quickly

Answer 1

Answer:o2=320g

MgO=800g

Explanation:

Calculate the moles than compare mole ratio after that calculate the grams

Answer 2

Answer: 320 g of oxygen is required and 800g of magnesium oxide( MgO) is formed in this reaction.

Explanation:

The reaction is given as:

Mg + 1/2 O2 --------> MgO

[Molecular mass of O2- 32g

Molecular mass of Mg- 24g

Molecular mass of MgO- 40g]

Now solving it,

According to the reaction, 1 mole of magnesium( mass- 24g) reacts with half a mole of oxygen( mass- 16g) to produce a mole of magnesium oxide( mass- 40g)

So, Amount of oxygen required for combustion of 24g of magnesium/ 1 mole = 16g

So, Amount of oxygen required for 480g of magnesium = (16/24) × 480 = 320g

Again,

Amount of magnesium oxide formed from 1 mole / 24 g of magnesium = 40g

So, Amount of magnesium oxide formed from 480g of magnesium = (40/24) × 480 = 800g.