Question

How many gram of oxalic acidh2c2o4.2h2o are required to make 0.1 and 250 ml solution

Answer 1

Answer:

Explanation:

OXALIC  ACID = H₂C₂O₄.2H₂O.

MOLECULAR MASS = [2*1]+[12*2]+[16*4]+[2*18]

                                                                                [ H= 1, C=12,O=16,H₂O = 18]

                                  = 2+24+64+36

                                  = 126 G

MOLARITY = 0.1 M

VOLUME OF SOLUTION = 250 ML

GIVEN MASS ,X =?

MOLARITY = GIVEN MASS *1000

                    -----------------------------

            MOLAR MASS * VOL OF SOLUTION (ML)

0.1 = X*1000/126*250.

X = 0.1*12*250/1000

X = 25*12/1000

X = 0.3 G OF OXALIC ACID IS REQUIRED.

HOPE THIS HELPS.

Answer 2

Explanation:

Use formula of molarity.

Hope it helps

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