Question

how many gram of oxygen at stp is required to burn 60g C2H6

Answer 1

1 mole of any gas occupies 22.4 litres. For 60g of ethane we need = (78.4/30)*60=156.8L of oxygen

Answer 2

Answer:Answer: 156.8 L

Explanation:-

given mass of ethane = 60 g

Molar mass of ethane = 60g/mol

From the given balanced chemical equation:

2C2H6+7O2⇒2CO2+3H2O

2 moles of ethane require 7 moles of oxygen.

According to Avogadro's law, 1 mole of every gas occupies 22.4 L at STP.Thus 2 moles of ethane require=7*22.4 L of oxygen.