Question

how many gram of Oxygen gas contain the same number of molecules as 16 gram of Sulphur dioxide gas o=16u,s=32u​

Answer 1

Answer:

8g

Explanation:

S+O2 = SO2

Molecular weight of sulphur dioxide (SO2) = 32+2x16 = 64g

Given weight = 16g

Thus , no. of moles of SO2 =

given mass/molar mass = 16/64 = 1/4 moles

Therefore according to the equation 1/ 4 moles of sulphur(S) will react with 1/4 moles of oxygen gas(O2) to form 1/4 moles of SO2

Thus weight of oxygen gas (O2) =

no. of moles x molecular weight

= 1/4 * 32 = 8g