Question

how many gram of oxygen is required to burn 40 gram of sulphur​

Answer 1

Explanation:

Atomic mass of S = 32 u, (Ans. 40 g) 0= 16 u) 6.

Answer 2

S + O2 = SO2

32 (16*2)   (32+32)

32g of sulphur requires 32g of oxygen

therefore, 40g of sulphur requires 40*32/ 32

= 40g of O2

ie., 40g of O2 is required to burn 40g of sulphur