Question

how many gram of oxygen is required to react completely with 0.200 gram of hydrogen to yield water also calculate the amount of water formed

Answer 1

2h2 + o2 -------> 2h2o

2 mole of hydrogen will react completely with 1 mole of o2....

Or,

4g of hydrogen will react with 32g of o2 completely......

so 1g of h2 will require= 32/4 g of o2

.200g of h2 will require= 32 ×0.200/4

= 1.6g of o2

now....

2 mole of h2 will form 2 mole of water

Or,

4g of h2 will form 36g of water

then, .0.200g of h2 will form

=36 ×0.200/4 of water

=1.8g of water or 0.1mol of water.

Answer 2

Explanation:

2H2+ O2 ---->>> 2H20

2g producing 18g of h20

therfore 0.200 g produce = 18× 0.200/2

= 1.8gm