How many gram of Potassium chlorate is Required for getting 0.36 gram oxygon.
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Answer:
0.93gram
Explanation:
In one mole of KClO3 , the mass of oxygen is 16×3 = 48 gram. The molecular mass of Pottassium chlorate is 124gram. By stiochiometry , If mass of one substance is given , the mass of other substance can be calculated : O 16 gram : KClO3 124 gram now by comparison we can write , O 1 gram : KClO3 124 gram ÷ 16 gram = 2.583 , now for 0.36 gram oxygen, 2.583 × 0.36 =0.93gram.
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