how many gram of so3 are produced from 1 mole of s8
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Answer : The mass of SO_3SO
3
produced are, 640 grams.
Solution : Given,
Moles of S_8S
8
= 1 mole
Molar mass of SO_3SO
3
= 80 g/mole
The balanced chemical reaction will be,
S_8+12O_2\rightarrow 8SO_3S
8
+12O
2
→8SO
3
From the balanced reaction, we conclude that
1 mole of S_8S
8
react to give 8 moles of SO_3SO
3
Now we have to calculate the mass of SO_3SO
3
\text{Mass of }SO_3=\text{Moles of }SO_3\times \text{Molar mass of }SO_3Mass of SO
3
=Moles of SO
3
×Molar mass of SO
3
\text{Mass of }SO_3=(8mole)\times (80g/mole)=640gMass of SO
3
=(8mole)×(80g/mole)=640g
Therefore, the mass of SO_3SO
3
produced are, 640 grams.
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