Chemistry, asked by utkarshsingh2154, 8 months ago

How many gram of solute is required to prepare 1.0 L of 1 M CaCl2.6H20?
O a. 216 g
Ob. 200 g
c. None of the above
O d. 219 g

Answers

Answered by antu69

2

Answer:

d.219g

Explanation:

Here,

s=1M

v=1.0L

m=219

We know,

weight of solute,w=svm=1*1*219=219g(Ans)

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