Question

how many gram of water is needed to make 8mass percent solution of sodium carbonate if 4gram of sodium carbonate is available to make a solution?​

Answer 1

Answer:

by the question

$8 \times 4 = 32$

as we are mixing two chemicals

Answer 2

Explanation:

sodium bicarbonate= NaHCO3 - 84amu

=>Na + H2O + CO2

this indicates 84 grams of NaHCO3 requires 18 grams of H20

4 grams require 18×4/84=18/21=6/7 grams

percentage = 6/7/4×100 = 600/28= 150/7 ≈ 21.4%

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