Question

How many grams are in 1.20 x 10^26 atoms of aluminum metal?

Answer 1

Answer:

Taking the Avogadro's constant as 6×10²³ the mass is approx 5400 grams.

Explanation:

$\frac{mass(g)}{molarmass} =\frac{no.of molecules}{6*10^{23} } \\\frac{mass(g)}{27} =\frac{1.2*10^{26} }{6*10^{23} } \\mass(g)=\frac{12*10^{25} }{6*10^{23} } * 27\\=2*10^{2} *27\\=5400$

HOPE THIS HELPS :)