Question

How many grams are in 14.5 moles of sodium fluoride?

Answer 1

Answer:

Given:

Moles of Sodium Fluoride (n) = 4.5

To find:

Mass of 4.5 moles of Sodium Fluoride = ?

Formula to be used:

Number of moles = \frac{Mass}{Molar mass}Numberofmoles=

Molarmass

Mass

Calculation:

The molar mass of Sodium Fluoride

=1(Atomic weight of Na)+1(Atomic weight of F)

= 1(23) + 1(19)

=23+19

= 42

∴Molar mass of Sodium Fluoride = 42

As the molar mass and number of moles are found, weight can be calculated using the formula

Number of moles = \frac{Mass}{Molar mass}Numberofmoles=

Molarmass

Mass

Number of moles × Molar mass = Mass

4.5 × 42= Mass

189 =Mass

Conclusion: in

The mass of 4.5 moles of sodium fluoride is 189g.

I hope this helps please give me brilliance or whatever it is:)

Answer 2

Moles of sodium fluoride = 14.5

We have to find out mass of sodium fluoride ( NaF)

We know that :-

$\boxed{ {\boxed{ \tt\large mass = n \times molar \: mass}}} \\ \\ \sf \: where \: n \: is \: number \: of \: moles$

$\tt\large \implies mass \: of \: NaF= n \times molar \: mass \: of \: NaF$

Molar mass of NaF :- 23 + 19

=> 23 + 19

=> 42 u

$\tt\large \implies mass \: of \: NaF= 14.5 \times 42$

$\tt\large \implies mass \: of \: NaF= \dfrac{6090}{10} = 6090$

Answer :

Mass of sodium fluoride in 14.5 moles = 609 grams.

Additional -Information :-

$\rm n = \dfrac{number \: of \: atoms}{N_A} \\ \\ \sf where : N_A = 6.022 \times {10}^{23} and \: n \: is \: number \: of \:moles$

$\rm n = \dfrac{mass}{molar \: mass}$