Question

how many grams are in 2.3 x10-4 moles of calcium phosphate

Answer 1

Multiply the number of moles with the molar mass of calcium phosphate

Answer 2

Answer : The grams in $2.3\times 10^{-4}$ moles of calcium phosphate is, $713.414\times 10^{-4}g$

Solution : Given,

Moles of calcium phosphate = $2.3\times 10^{-4}$

Molar mass of calcium phosphate = 310.18 g/mole

Formula used : $Moles=\frac{\text{Given mass}}{\text{Molar mass}}$

$\text{Moles of }Ca_3(PO_4)_2=\frac{\text{Mass of }Ca_3(PO_4)_2}{\text{Molar mass of }Ca_3(PO_4)_2}$

$2.3\times 10^{-4}moles=\frac{\text{Mass of }Ca_3(PO_4)_2}{310.18g/mole}$

$\text{Mass of }Ca_3(PO_4)_2}=713.414\times 10^{-4}g$

Therefore, the grams in $2.3\times 10^{-4}$ moles of calcium phosphate is, $713.414\times 10^{-4}g$