Question

How many grams are in 4.5 moles of sodium fluoride?

Answer 1

mass of sodium is 23 and mass of fluirine is 19 there mass of NaF is 42
42 g = 1 mole therefor 4.5 moles will have
4.5 × 42 = 189 g

Answer 2

Given:

Moles of Sodium Fluoride (n) = 4.5

To find:

Mass of 4.5 moles of Sodium Fluoride = ?

Formula to be used:

$Number of moles = \frac{Mass}{Molar mass}$

Calculation:

The molar mass of Sodium Fluoride

=1(Atomic weight of Na)+1(Atomic weight of F)

= 1(23) + 1(19)

=23+19

= 42

∴Molar mass of Sodium Fluoride = 42

As the molar mass and number of moles are found, weight can be calculated using the formula

$Number of moles = \frac{Mass}{Molar mass}$

Number of moles × Molar mass = Mass

4.5 × 42= Mass

189 =Mass

Conclusion:

The mass of 4.5 moles of sodium fluoride is 189g.

Learn more about such concept

Obtain the moles of substances in the following.

2.57 g As

https://brainly.in/question/1247974

Question 8 Convert into mole. (a) 12 g of oxygen gas (b) 20 g of water (c) 22 g of carbon dioxide

https://brainly.in/question/1301685