How many grams are in 8.200 x 1022 molecules of N2I6?
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Answer:
8.2 * 10^22 molecules N2I6 * (1 mol N2I6 / 6.022 * 10^23 molecules N2I6) * (789.42 g N2I6 / 1 mol N2I6) = 107.49 g N2I6
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