Chemistry, asked by dsanzharboss, 4 months ago

How many grams are there in 0.7 mol of Fe(NO3)3?

Answers

Answered by mustafizurrahman8651

0

Answer:

169.26g

Explanation:

mr value = 55.8+[14+(16*3)]*3

= 241.8 g

1 moles = 241.8 g

so,0.7 moles = (241.8*0.7) g

= 169.26 g

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