Question

How many grams are there in 2.30 x 1024 atoms of silver?

Answer 1

Answer:

u have to take this no ND in upon u have to divide it by Avogadro's no.

Answer 2

Final answer: $411.988$ $g$ are there in $2.3\times 10^{24}$ atoms of silver.

Given that: We are given $2.30 \times 10^{24}$ atoms of silver.

To find: We have to find how many grams are there in $2.30 \times 10^{24}$ atoms of silver.

Explanation:

• $1$ $mol$ any substance contains Avogadro’s number of atoms.
• $1$ $mol$ any substance = $6.022\times 10^{23}$ atoms
• Therefore $1$ $mol$ silver contains $6.022\times 10^{23}$ silver atoms.
• Number of moles of silver in $1$ atoms = $\frac{1}{6.022 \times 10^{23}}$ $mol$
• Number of mol of silver in $2.3 \times 10^{24}$ atoms $=\frac{1}{6.022\times 10^{23}} \times (2.3\times 10^{24})$

$=\frac{2.3 \times 10^{24}}{6.022 \times 10^{23}}$

$=3.8193$ $mol$

• The molecular mass of silver $=107.87 \frac{g}{mol}$

$Number of moles of silver = \frac{Given mass of silver}{Molecular mass of silver}$

$Given mass of silver = (Number of moles of silver) \times (Molecular mass of silver)$

• Substitute the values of the molecular mass of silver and the number of moles of silver.

$Given mass of silver = (3.8193 mol) \times (107.87 \frac{g}{mol})$

$=3.8193 \times 107.87 = 411.988$ $g$

• The mass of $2.3\times 10^{24}$ atoms of silver $= 411.988$ $g$
• Therefore, $411.988$ $g$ are there in $2.3\times 10^{24}$ atoms of silver.

To know more about the concept please go through the links

https://brainly.in/question/2020181

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