Question

How many grams are there in 3.30 x10^23 molecules of N2I6

Answer 1

Answer:

Hope it help you

stayhomestaysafe

plz mark my answer brainiest

Explanation:

3.3 x10^23 molecules N2I6 ( 1 mol N2I6 / 6.022 x10^23 molecules) X (789.438 g / 1 mol N2I6) = 432.604 g N2I6

@Shresthdubey

Answer 2

Given:

The number of molecules in the sample of N₂I₆ = 3.30 X 10²³

To Find:

The number of grams in the given sample

Solution:

The number of grams in the given sample is 434.5 g.

One mole of a substance has exactly 6.022 X 10²³ elemental units. These elemental units can be molecules, ions, or atoms depending on the substance.

If 6.022 X 10²³ molecules of N₂I₆ constitute 1 mole of the substance,

Then 1 molecule will constitute $\frac{1}{6.022X10^2^3}$ moles of the substance.

⇒ 3.30 X 10²³ molecules of N₂I₆ will have 3.30 X 10²³ /  6.022 X 10²³ moles

= 3.300 / 6.022

= 0.55 moles

We know that the mass of 1 mole of a substance is equal to its molar mass.

The molar mass of N₂I₆ = 2 X Molar mass of N + 6 X Molar mass of I

= 2 X 14 + 6 X 127

= 28 + 762

= 790 g

Thus 1 mole of N₂I₆ will weigh 790g

⇒ 0.55 moles will weigh 790 X 0.55 g

= 434.5 g