Question

How many grams are there in 4.50 moles of Ba(No2)2

Answer 1

Answer:

1031.85 grams

Explanation:

number of moles (n) = 4.50 moles

mass (m) = n×M

[This is what you are trying to find]

molar mass (M) = ?

Your first step is to find out what is the molar mass (M) of Ba(NO2)2.

To find a molar mass of a compound, break the compound up into component parts so you could see what elements are involved.

If you break Ba(NO2)2 up, you can clearly see that it is composed of Ba, N and O.

You got to find the molar mass of each elements involved. You can identify the molar mass straight away if you look into the periodic table.

Ba = 137.3gmol−1

N = 14.0×2

because there is a number 2 after the closing bracket so

28.0gmol−1

O = There are 2 O atoms inside the bracket and doubled because of the 2 outside the closing bracket, so there are 4 O atoms altogether.

16.0gmol−1×4=64.0gmol−1

So to get the molar mass of

Ba(NO2)2, add the molar mass of the elements up.

137.3+28.0+64.0 and that will give you

229.3gmol−1 . Therefore the molar mass of Ba(NO2)2 is 229.3gmol−1 .

n = 4.50 moles

m = ?

M = 229.3 gmol−1

Step 2, you can now find the mass of

Ba(NO2)2 . To find the mass, you need to multiply the number of moles (n) with molar mass (M), in other words,

m=n×M

m=4.50×229.3=1031.85

Therefore, there are 1031.85 grams in 4.50 moles of

Ba(NO2)2 .

Answer 2

Answer:

number of moles (n) = 4.50 moles

mass (m) = n×m

molar mass (M) of Ba(NO2)2.

Ba = 137.3gmol−1

N = 14.0×2

28.0gmol−1

16.0gmol−1×4=64.0gmol−1

137.3+28.0+64.0  

229.3gmol−1 . Therefore the molar mass of Ba(NO2)2 is 229.3gmol−1 .

n = 4.50 moles

 M = 229.3 gmol−1

m=n×M

m=4.50×229.3=1031.85

Therefore, there are 1031.85 grams in 4.50 moles of

Ba(NO2)2 .

Explanation: