Question

How many grams are there in 53 grams of Na2CO3?​

Answer 1

sodium carbonate has a molecular weight of 106grams /mol. That 53is half of 106, so that means 0.5mole of compound as well as 0.5Na,which has a molecular weight of 23, so 11.5grams of sodium is there.

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Answer 2

Answer:

$23$ gram of Na in $53$gram of Na$2$CO$2$

Explanation:

  Sodium carbonate contains two atoms of sodium three atom of
oxygen and one atom of carbon , therefore we can calculate the
  Molecular weight of sodium carbonate (Na$2$CO$2$) = $106$ gram/mole

   Number of moles in each (Na$2$CO$2$ )= Gram weight÷ Atomic mass
                                                                 = $0.5$moles
     
     Number of mole in Na =  $2$× $0.5$
                                             = 1 mole of Na
     
      Molecular weight of Na = $23$gram / mole
   
     Therefore in 53 gram of Na2CO3 there should be = $23$ ×$1$
                                                                                           = $23$ gram of Na
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