Question

How many grams atoms are present in 69g of sodium

Answer 1

Atomic weight of a sodium atom is 23g. Number of protons in each sodium atoms is 11. Now follow the above method and find out the answer. In 69 g of sodium, there are 3 moles & hence 18.066 × 10^23 atoms.
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Answer 2

The gram atoms in 69g of sodium is $18.07\times 10^{23}$

Explanation:

According to avogadro's law, 1 mole of every substance occupies 22.4 L at STP and contains avogadro's number $6.023\times 10^{23}$ of particles.

To calculate the moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text {Molar mass}}=\frac{69g}{23g/mol}=3moles$

1 mole of sodium $(Na)$ = $6.023\times 10^{23}$ gram atoms of sodium $(Na)$

3 moles of sodium $(Na)$ = $\frac{6.023\times 10^{23}}{1}\times 3=18.07\times 10^{23}$ gram atoms of sodium $(Na)$

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