Chemistry, asked by fayefaye, 11 months ago

How many grams MgCl 2 will be needed to prepare 3000 grams of a 0.8 molal solution?

Answers

Answered by sadiamemon364

5

Answer:

228 grams

Explanation:

molality =mass of solute x 1000/ gram formula mass of solute x mass of solvent

0.8= mass of solute x 1000/ 95 x 3000

0.8 = mass of solute x 1000/ 285000

0.8 = mass of solute x 0.0035

0.8 / 0.0035 = mass of solute

228 = mass of solute

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