Question

How many grams o2 is required to burn 570 g of octane?

Answer 1

According to chemical reaction,

If 228g of octane = 800g of O2

reacts with

1g of octane reacts with = 800/228 g of

O2

570 g of octane reacts with = 800 x 570

228

=2000g of O2

Thus 2000g of O2 is required to react with 570g of octane .