Question

How many grams of 90% pure na2so4 can be produced from 250 gm of 95% pure nacl?

Answer 1

According to given reaction ,

$2NaCl + H_{2}SO_{4} = Na_{2}SO_{4}  + 2HCl$

2 moles of NaCl gives 1 moles of sodium sulfate

$Mass of NaCl = \frac{250*95}{100} = 237.5 g$

$Moles of NaCl = \frac{237.5}{58.5} = 4.06 moles$

According to above chemical reaction,

$4.06 moles of NaCl give = \frac{4.06}{2} = 2.03 moles of sodium sulfate$

Mass of sodium sulfate = 2.03×142.04 = 288.33 g

Mass of 90% pure sodium sulfate = $\frac{288.33*90}{100} = 259.5 g$

Thus, the mass of pure sodium sulfate = 259.5 g  

Answer 2

It's the correct answer. Hope I was helpful to you...