How many grams of a 15 percent alcohol solution should be mixed with 40 grams of a 30 percent solution to obtain a solution that is 25 percent alcohol?
Answers
Given : Few grams of a 15 percent alcohol solution mixed with 40 grams of a 30 percent solution to obtain a solution that is 25 percent alcohol
To Find : How many grams of a 15 percent alcohol solution mixed
Solution:
Ley sat x gram of 15 percent alcohol solution mixed
=> Alcohol = (15/100)x = 0.15x grams
40 grams of a 30 percent solution
=> Alcohol = (30/100)40 = 12 grams
Total Alcohol = 0.15x + 12 grams
Total Mixture = x + 40 grams
solution that is 25 percent alcohol
=> (25/100) (x + 40) = 0.15x + 12
=> x + 40 = 0.6x + 48
=> 0.4x = 8
=> 4x = 80
=> x = 20
Hence 20 grams of a 15 percent alcohol solution to be mixed
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