Question

how many grams of a maximum zinc chloride can be formed from the reaction between 6.5 gram of zinc and 3.2 gram of HCL​

Answer 1

Zn(s]+2HCl(aq]→ZnCl2(aq]+ H2(g]↑⏐ ... with a single replacement reaction in which zinc displaces the ... The products of the reaction are aqueous zinc ..

Answer 2

Answer: The mass of zinc chloride formed will be 5.928 grams.

Explanation:

To calculate the moles of a substance, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$     ......(1)

• For Zinc:

Given mass = 6.5 g

Molar mass = 65.38g/mol

Putting values in equation 1, we get:

$\text{Moles of zinc}=\frac{6.5g}{65.38g/mol}=0.099mol$

• For Hydrochloric acid:

Given mass = 3.2 g

Molar mass = 36.5g/mol

Putting values in equation 1, we get:

$\text{Moles of hydrochloric acid}=\frac{3.2g}{36.5g/mol}=0.087mol$

The reaction between zinc and hydrochloric acid follows the equation:

$Zn+2HCl\rightarrow ZnCl_2+H_2$

By Stoichiometry:

2 moles of hydrochloric acid reacts with 1 mole of zinc metal.

So, 0.087 moles of hydrochloric acid reacts with = $\frac{1}{2}\times 0.087=0.0435moles$ of zinc metal.

As, moles required is less than the given amount. So, zinc metal is present in excess. Thus, it is considered as an excess reagent.

Thus, hydrochloric acid is considered as a limiting reagent because it limits the formation of product.

By Stoichiometry of the reaction:

2 moles of hydrochloric acid produces 1 mole of zinc chloride.

So,0.087 moles of hydrochloric acid produces = $\frac{1}{2}\times 0.087=0.0435moles$ of zinc chloride.

Now, to calculate the mass, we use equation 1, we get:

Moles of zinc chloride = 0.0435 mol

Molar mass of zinc chloride = 136.286 g/mol

Putting values in equation 1, we get:

$0.0435mol=\frac{\text{Mass of zinc chloride}}{136.286g/mol}\\\\\text{Mass of zinc chloride}=5.928g$

Hence, the mass of zinc chloride formed will be 5.928 grams.