Question

how many grams of Ag will be deposited if 5 F quantity of electricity is passed through aqueous solution of AgNO3​

Answer 1

The number of grams of silver that will be deposited due to electrolysis of aqueous solution of silver nitrate is found by the faraday's law.

Explanation:

• According to the Faraday's law, the mass of silver that will be deposited is equal to the product of the charge and the  molecular weight of silver.

• m=z×Q= 96500/ E×Q, the amount of charge that is passeg is equal to 5 Faraday.

​Or, m= 96500x 108 ×5/ 96500=540 gm

• from the above equation we see that the weight of the deposited substance is dependent on the molecular weight and the amount of charge

To know more,

In electrolysis, amount of silver deposited equivalent of 112 ml of ..

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