Question

How many grams of ammonia are present in 5.0 L of a 0.05 M solution?

Answer 1

Given:

Volume, V=5L

Molarity, M=0.05mol/L

as Molar mass of NH₃(ammonia) is 17g

We know that,

M=[m]÷[V(L)×M.M.]

⇒m=M×M.M.×V

∴ m=0.05mol/L×17g×5L

⇒m=4.25g

Answer 2

Answer:

previous answer is absolutely correct answer.