Chemistry, asked by Anonymous, 9 months ago

How many grams of ammonia are present in 5.0 L of a 0.05 M solution?

Answers

Answered by ShresthaTheMetalGuy
3

Given:

Volume, V=5L

Molarity, M=0.05mol/L

as Molar mass of NH₃(ammonia) is 17g

We know that,

M=[m]÷[V(L)×M.M.]

⇒m=M×M.M.×V

∴ m=0.05mol/L×17g×5L

m=4.25g

Answered by rakesh5877
0

Answer:

previous answer is absolutely correct answer.

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