How many grams of ammonia will contain the same number of molecules as 1.1 g of CO2.(C = 12, O = 16,N = 14,H = 1)
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the total molecules of CO2= 12+32 =44
1.1g of 44 = 44*1.1=48.4
moles of ammonia NH3 = 17
therefore grams of ammonia needed =
48.4/17=2.84
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