Question

how many grams of ammonium sulphate will be required to prepare 6.8 gram of ammonium sulphate with caustic soda solution?

Answer 1

Answer:

0.25 L of a solution with a molarity of 6M has 6*0.25 = 1.5 moles of the solute. The molar mass of ammonium sulfate is 132.14 g/mole. The mass of 1.5 moles is 132.14*1.5 = 198.21 g. Therefore 198.12 g of ammonium sulfate are required to make 0.25 L of a solution with a concentration of 6M.

Explanation:

Answer 2

Answer:

o.25 l of solution with a molarity of 6m has 6*0.25 =15 moles of the solute the molar mass of ammonium sulphate is 132.14 g/mole .the mass of 1.5 moles is 132 .14*15 =198.219 .therefore 197.128 of ammonium sulphate are required to make 0.25 l of solution with a solution with a concentration of 6ml

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