Question

how many grams of Bacl2 are needed to prepare 100cm cub
e of a 250 M Bacl2??​

Answer 1

Answer:

$Heya \: user$............❤

Here, molar mass of BaCl2. 2 H2O ( BaCl2 solution)

= 137 × 35.5×2 +2×18

= 244 u

Notes : M = Moles/ V(L)

= (gM/ MM) × 100/V(ml)

u + 0.250 = x/(244/100)× 1000

= 6.1 g

Hope it’s helpful....... ☺