Question

How many grams of barium chloride are needed to make 100cm3 of 0.250m bacl2 solution?

Answer 1

I couldn't interpret the question correctly, the m, is it small or capital?

I'd solve it as capital.

Molarity=No of moles/ Volume in ml * 1000.

Here, 0.25= 1000n/ 100

Thus n is 0.025 moles.

Thus mass required = 0.025 * ( 137+71)

If wrong. please inform, if correct, approve.