Question

How many grams of beryllium chloride are needed to make 125 mL of a 0.05M solution?

Answer 1

Molarity=0.05M

Volume =125ml=0.125L

Molarity =moles /volume

Moles =0.05×0.125

Moles=0.00625

Moles =weight/mol wt

Mol wt of BeCl2 is=80g

0.00625×80=weight

Weight=0.5 g

I hope this helps ( ╹▽╹ )