Question

How many grams of caco3 produced from 62.3 g of Na2co3

Answer 1

Answer:

Na2CO3 + Ca(NO3)2  CaCO3 + 2NaNO3

1. Find chemical amount of sodium carbonate (Na2CO3):

m= Mn, then n= m/M;

M(Na2CO3) = 22.992 + 12.01+16.003 = 105.99 (g/mol);

n(Na2CO3) = 85.5 /105.99 =0.81 (mole).

2. Find chemical amount of calcium carbonate (CaCO3):

According to equation of chemical reaction 1 mole of Na2CO3 gives 1 mole of CaCO3, i.e.

n(Na2CO3) = n(CaCO3);

n(CaCO3) = 0.81 mol

Answer: 0.81 mol

Explanation:

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