Question

How many grams of CaCO3

will be needed for the preparation of 22 g of CO2

by reaction with dilute Hcl and

Calcium Carbonate? (Ca=40, C=12)​

Answer 1

CaCO3 +2HCl→CaCl2+H2O+CCO ↑

1 mole of calcium carbonate gives 1 mole of CO2

Molar mass of calcium carbonate =40+12+3(16)=100 g/mol.

150 grams of calcium carbonate corresponds to

100 g/mol

150 g

=1.50 moles of calcium carbonate.

They will give 1.50 moles of CO2

.

The molar mass of CO2

is 44 g/mol.

Mass of CO2

=1.5 mol×44g/mol=66 mol