Chemistry, asked by sivaprakash49941, 16 days ago

How many grams of calcium carbonate are needed to form 482 grams of calcium carbide?

Answers

Answered by dhruvohlan403
0

Answer:

We are told that

CaCO

3

is in excess, so clearly,

C

is the limiting reactant. Therefore, since

5 mols C

form

2 mols CaC

2

, we scale the reaction down to get:

4

5

×

(

2

CaCO

3

(

s

)

+

5

C

(

gr

)

Δ

−−→

2

CaC

2

(

s

)

+

3

CO

2

(

g

)

)

Now we read directly from the re-scaled balanced reaction that:

4

5

×

5 mols C

forms

4

5

×

2

=

8

5

mols CaC

2

.

If the molar mass of

CaC

2

is

64.099 g/mol

, how many grams of

CaC

2

involves

8

5

mols

of it? Your answer must be larger than

64.099 g

to make physical sense.

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