Question

how many grams of calcium carbonate will be needed for the preparation of 22g of carbon dioxide by reaction with h dilute hydrochloric acid to calcium carbonate​

Answer 1

Answer:

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Explanation:

CaCO

3

+2HCl→CaCl

2

+H

2

O+CO

2

↑

1 mole of calcium carbonate gives 1 mole of CO

2

Molar mass of calcium carbonate =40+12+3(16)=100 g/mol.

150 grams of calcium carbonate corresponds to

100 g/mol

150 g

=1.50 moles of calcium carbonate.

They will give 1.50 moles of CO

2

.

The molar mass of CO

2

is 44 g/mol.

Mass of CO

2

=1.5 mol×44g/mol=66 mol