HOW MANY GRAMS OF CALCIUM FLUORIDE CANTAIN 38g OF FLUORIDE ATOMS ?????
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Answered by
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38 g of F = 2 moles so you need 1 mole of CaF2.
1 mole of CaF2 * 78.07 g/mole = 78.07 g CaF2
1 mole of CaF2 * 78.07 g/mole = 78.07 g CaF2
Answered by
9
Answer:
38 g of F = 2 moles so you need 1 mole of CaF2 is the answer.
Explanation
HOW MANY GRAMS OF CALCIUM FLUORIDE CANTAIN 38g OF FLUORIDE ATOMS IS 38 g of F = 2 moles so you need 1 mole of CaF2.
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