How many grams of calcium ions are in 2.14 m calcium ion?
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Kalahira. 1.8 x 10^23 calcium ions Each mole of CaCl2 will produce 1 mole of calcium ions. So just multiply the number of moles of CaCl2 by avogadro's number. Therefore 0.3 * 6.0221409 x 10^23 = 1.806642 x 10^23 So there will be 1.8 x 10^23 calcium ions in 0.3 moles of CaCl2.
Explanation:
Calculate the moles of EDTA in the average titre: moles(EDTA) = concentration (mol L-1) x volume (L) = 0.010 x 8.78 x 10-3 = 8.78 x 10-5 mol.
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