Question

How many grams of carbon is present in 250gram of caco3.​

Answer 1

=250⋅g100.09⋅g⋅mol−1formula mass of calcium carbonate=2.50⋅mol ... ...and thus there are 2.50⋅mol of calcium atoms present, 2.50⋅mol of carbon atoms present, and 7.50⋅mol of oxygen atoms present; are you clear as to how we got these numbers?

hope it's help uh

Answer 2

Answer:

1g of CaCO3 will contain 6.022*10^23/100=6.022 * 10^21 carbon atoms.

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