Question

how many grams of Cd(no3)2 . 4h20 are required to prepare 250ml of its 2.5 m solution??
pls give relevant and correct answer as I'm asking this for the 4th time​

Answer 1

Answer:

I suppose you mean 2.5 M i.e molarity and not molality

so now moles = molarity * volume

= 2.5 *250/1000 = 0.625

so now moles = given mass / molecular mass

molecular mass =( approx) 308 g/mol

so 0.625 * 308 =192.5 gm

hope this helps