Question

How many grams of Cd(NO3)2 .4H2O are required to prepare 250 ml of its 2.5 M

solution? (Cd=112.4 g/mol)​

Answer 1

Answer:

A bit over

2

⋅

g

...............

Explanation:

Concentration

=

Moles of solute (moles)

Volume of solution (L)

Thus

Concentration

×

volume

=

moles of solute

0.205

⋅

m

o

l

⋅

L

−

1

×

0.250

⋅

L

=

Moles of solute

=

0.0513

⋅

m

o

l

, an answer in moles as required.

And thus

mass of NaOH

=

moles

×

molar mass

=

0.0513

⋅

m

o

l

×

40.0

⋅

g

⋅

m

o

l

−

1

=

2.05

⋅

g