Question

How many grams of ch3oH should be added to water to prepare 150 ml solution of 2 M ch3oH?

Answer 1

molarity =no of mole of solute/volume of solution in litre
2M=no of mole of CH3OH/(150/1000)L
15x2/1000=mole of CH3OH
mole of CH3OH=0.03
weight of CH3OH=0.03xmolar weight of CH3OH=0.03x32=0.96g

Answer 2

Explanation:

How many grams of ch3oH should be added to water to prepare 150 ml solution of 2 M ch3oH?