Question

how many grams of Cl2 is produced in reaction with 15.8 gram of KMnO4 and 50 ml of 10M HCL

2KMnO4+16HCl--->2KCl+MnCl2+8H2O+ Cl​

Answer 1

Hi mate

16HCl + 2KMnO4 ------> 2KCl + 2MnCl2 + 5Cl2 + 8H2O

The equation is balanced and gives proper stoichiometry. This is a redox reaction involving HCl and KMnO4.

According to stoichiometry of the reaction 2 moles of KMnO4 will produce 8 moles of H2O. That means 1 mol of KMnO4 will produce exactly 4 moles of H2O (since 8/2 = 4).

In the same manner, 2 moles of KMnO4 will produce 2 moles of KCl according to stoichiometry. Therefore 1 mol of KMnO4 will produce 1 mol of KCl. To find the mass of KCl produced we need to find the molar mass of KCl.

Molar mass of KCl = Molar mass of K + Molar mass of Cl

= 39 + 35.5

= 74.5 g per mol

The mass of KCl produced = 1 mol x 74.5 g per mol

= 74.5 g.

Therefore 1 mol of KMnO4 will produce 74.5 g of KCl.