Question

How many grams of CO2 and grams of H2O are produced when 52.0 g C2H2 burn in oxygen?

Answer 1

2C2H2 + 5O2 --> 4CO2 + 2H2O

1 mole of C2H2 = 2 (12.0) + 2(1.0) = 26.0 g

1 mole of CO2 = 12.0 + 2 (16.0) = 44.0 g

1 mole of H2O = 2(1.0) + 16.0 = 18.0 g

52 g C2H2 x 1 mol / 26 g = 2.0 mol C2H2

2.0 mol C2H2 x 4 CO2 / 2 C2H2 = 4.0 mol CO2

4.0 mol CO2 x 44.0 g / mol = 176 g CO2

52 g C2H2 x 1 mol / 26 g = 2.0 mol C2H2

2.0 mol C2H2 x 2 H2O / 2 C2H2 = 2.0 mol H2O

2.0 mol H2O x 18.0 g / mol = 36 g H2O