How many grams of co2 is formed when 73.9g of propane is
burnt
Answers
Answer:
66 grams of Carbon Dioxide.
Explanation:
The common currency of chemistry is moles. So it is necessary to change the mass of propane to moles. Then write a balance equation so the moles of propane to moles of Carbon Dioxide. Finally moles of Carbon Dioxide must be changed to grams.
C
3
H
8
+
5
O
2
=
=
3
C
O
2
+
4
H
2
O
This is the balance equation for the burning of propane in Oxygen.
From the equation it can be seen that 1 mole of propane makes 3 moles of Carbon Dioxide a ratio of 1:3
Convert 22 grams of propane to moles by dividing by the molar mass of propane.
3 x 12 = 36 grams
1 x 8 = + 8 grams
total = 44 grams/ mole.
22
44
= .5 moles of propane.
Using the ratio of 1:3 .5 = 3( .5) = 1.5 moles of Carbon Dioxide.
Now multiply 1.5 moles of Carbon Dioxide by the molar mass of Carbon Dioxide
1 x 12 = 12 grams
2 x 16 = +32 grams
total = 44 grams /mole.
1.5 moles x 44 grams/mole = 66 grams.